破解aes加密的易语言程序（易语言 aes解密）
破解aes加密的易语言程序（易语言 aes解密）
一般的主流加密方式的算法是一样的，不受平台、语言影响。
比如：AES、RC4、DES，等等
无论什么编程语言，都是使用这些加密的算法进行编写。它们最后加密后的都是一样的文本型或字节集型数据，这个语言用AES加密的另个语言中用AES自然也可以解密。
所以，本来就是通用的。
如果你是程序开发人员，应该有自己动手查找资源的能力啊，这个AES很好找啊。
这个是github上的专门为嵌入式优化过的，作者介绍ARM上大概使用200 bytes RAM 和 2.5K ROM
为防你上不了github，我直接下下来做了个附件
有界面，我这里有个，但是是c#语言的，你以为如何？
下面是c版本的
AES加密算法源代码
//AES.h
#define decrypt TRUE
#define encrypt FALSE
#define TYPE BOOL
typedef struct _AES{
int Nb;
int Nr;
int Nk;
unsigned long *Word;
unsigned long *State;
}AES;
/*
加密数据
byte *input 明文
byte *inSize 明文长
byte *out 密文存放的地方
byte *key 密钥key
byte *keySize 密钥长
*/
void Cipher(
unsigned char* input,
int inSize,
unsigned char* out,
unsigned char* key,
int keySize);
/*
解密数据
byte *input 密文
int *inSize 密文长
byte *out 明文存放的地方
byte *key 密钥key
int *keySize 密钥长
*/
void InvCipher(
unsigned char* input,
int inSize,
unsigned char* out,
unsigned char* key,
int keySize);
/*
生成加密用的参数AES结构
int inSize 块大小
byte* 密钥
int 密钥长
unsigned long 属性(标实类型)
返回AES结构指针
*/
AES *InitAES(AES *aes,
int inSize,
unsigned char* key,
int keySize, TYPE type);
/*
生成加密用的参数AES结构
int inSize 块大小
byte* 密钥
int 密钥长
返回AES结构指针
*/
AES *InitAES(
int inSize,
unsigned char* key,
int keySize, BOOL );
/*
加密时进行Nr轮运算
AES * aes 运行时参数
*/
void CipherLoop(
AES *aes);
/*
解密时进行Nr轮逆运算
AES * aes 运行时参数
*/
void InvCipherLoop(
AES *aes);
/*
释放AES结构和State和密钥库word
*/
void freeAES(
AES *aes);
//AES.cpp
#include "stdafx.h"
#include
#include
#include "AES.h"
unsigned char* SubWord(unsigned char* word);
unsigned long* keyExpansion(unsigned char* key, int Nk, int Nr,int);
/*
加密数据
byte *input 明文
byte *inSize 明文长
byte *out 密文存放的地方
byte *key 密钥key
byte *keySize 密钥长
*/
void Cipher(unsigned char* input, int inSize, unsigned char* out, unsigned char* key, int keySize)
{
AES aes ;
InitAES(aes,inSize,key,keySize,encrypt);
memcpy(aes.State,input,inSize);
CipherLoop(aes);
memcpy(out,aes.State,inSize);
}
/*
解密数据
byte *input 密文
int *inSize 密文长
byte *out 明文存放的地方
byte *key 密钥key
int *keySize 密钥长
*/
void InvCipher(unsigned char* input, int inSize, unsigned char* out, unsigned char* key, int keySize)
{
AES aes;
InitAES(aes,inSize,key,keySize,decrypt);
memcpy(aes.State,input,inSize);
InvCipherLoop(aes);
memcpy(aes.State,out,inSize);
}
/*
生成加密用的参数AES结构
int inSize 块大小
byte* 密钥
int 密钥长
返回AES结构指针
*/
AES *InitAES(AES *aes,int inSize, unsigned char *key, int keySize, TYPE type)
{
int Nb = inSize 2,
Nk = keySize 2,
Nr = Nb Nk ? Nk:Nb+6;
aes-Nb = Nb;
aes-Nk = Nk;
aes-Nr = Nr;
aes-Word = keyExpansion(key,Nb,Nr,Nk);
aes-State = new unsigned long[Nb+3];
if(type)
aes-State += 3;
return aes;
}
/*
生成加密用的参数AES结构
int inSize 块大小
byte* 密钥
int 密钥长
返回AES结构指针
*/
AES *InitAES(int inSize, unsigned char* key, int keySize,unsigned long type)
{
return InitAES(new AES(),inSize,key,keySize,type);
}
/*
*/
void CipherLoop(AES *aes)
{
unsigned char temp[4];
unsigned long *word8 = aes-Word,
*State = aes-State;
int Nb = aes-Nb,
Nr = aes-Nr;
int r;
for (r = 0; r Nb; ++r)
{
State[r] ^= word8[r];
}
for (int round =1; round {
word8 += Nb;
/*
假设Nb=4;
---------------------
| s0 | s1 | s2 | s3 |
---------------------
| s4 | s5 | s6 | s7 |
---------------------
| s8 | s9 | sa | sb |
---------------------
| sc | sd | se | sf |
---------------------
| | | | |
---------------------
| | | | |
---------------------
| | | | |
---------------------
*/
memcpy(State+Nb,State,12);
/*
Nb=4;
---------------------
| s0 | | | |
---------------------
| s4 | s5 | | |
---------------------
| s8 | s9 | sa | |
---------------------
| sc | sd | se | sf |
---------------------
| | s1 | s2 | s3 |
---------------------
| | | s6 | s7 |
---------------------
| | | | sb |
---------------------
*/
for(r =0; r {
/*
temp = {Sbox[s0],Sbox[s5],Sbox[sa],Sbox[sf]};
*/
temp[0] = Sbox[*((unsigned char*)State)];
temp[1] = Sbox[*((unsigned char*)(State+1)+1)];
temp[2] = Sbox[*((unsigned char*)(State+2)+2)];
temp[3] = Sbox[*((unsigned char*)(State+3)+3)];
*((unsigned char*)State) = Log_02[temp[0]] ^ Log_03[temp[1]] ^ temp[2] ^ temp[3];
*((unsigned char*)State+1) = Log_02[temp[1]] ^ Log_03[temp[2]] ^ temp[3] ^ temp[0];
*((unsigned char*)State+2) = Log_02[temp[2]] ^ Log_03[temp[3]] ^ temp[0] ^ temp[1];
*((unsigned char*)State+3) = Log_02[temp[3]] ^ Log_03[temp[0]] ^ temp[1] ^ temp[2];
*State ^= word8[r];
State++;
}
State -= Nb;
}
memcpy(State+Nb,State,12);
word8 += Nb;
for(r =0; r {
*((unsigned char*)State) = Sbox[*(unsigned char*)State];
*((unsigned char*)State+1) = Sbox[*((unsigned char*)(State+1)+1)];
*((unsigned char*)State+2) = Sbox[*((unsigned char*)(State+2)+2)];
*((unsigned char*)State+3) = Sbox[*((unsigned char*)(State+3)+3)];
*State ^= word8[r];
State++;
}
}
/*
解密时进行Nr轮逆运算
AES * aes 运行时参数
*/
void InvCipherLoop(AES *aes)
{
unsigned long *Word = aes-Word,
*State = aes-State;
int Nb = aes-Nb,
Nr = aes-Nr;
unsigned char temp[4];
int r =0;
Word += Nb*Nr;
for (r = 0; r Nb; ++r)
{
State[r] ^= Word[r];
}
State -= 3;
for (int round = Nr-1; round 0; --round)
{
/*
假设Nb=4;
---------------------
| | | | |
---------------------
| | | | |
---------------------
| | | | |
---------------------
| s0 | s1 | s2 | s3 |
---------------------
| s4 | s5 | s6 | s7 |
---------------------
| s8 | s9 | sa | sb |
---------------------
| sc | sd | se | sf |
---------------------
*/
memcpy(State,State+Nb,12);
/*
Nb=4;
---------------------
| | | | s7 |
---------------------
| | | sa | sb |
---------------------
| | sd | se | sf |
---------------------
| s0 | s1 | s2 | s3 |
---------------------
| s4 | s5 | s6 | |
---------------------
| s8 | s9 | | |
---------------------
| sc | | | |
---------------------
*/
Word -= Nb;
State += Nb+2;
for(r = Nb-1; r = 0; r--)
{
/*
temp = {iSbox[s0],iSbox[sd],iSbox[sa],iSbox[s7]};
*/
temp[0] = iSbox[*(byte*)State];
temp[1] = iSbox[*((byte*)(State-1)+1)];
temp[2] = iSbox[*((byte*)(State-2)+2)];
temp[3] = iSbox[*((byte*)(State-3)+3)];
*(unsigned long*)temp ^= Word[r];
*(unsigned char*)State = Log_0e[temp[0]] ^ Log_0b[temp[1]] ^ Log_0d[temp[2]] ^ Log_09[temp[3]];
*((unsigned char*)State+1) = Log_0e[temp[1]] ^ Log_0b[temp[2]] ^ Log_0d[temp[3]] ^ Log_09[temp[0]];
*((unsigned char*)State+2) = Log_0e[temp[2]] ^ Log_0b[temp[3]] ^ Log_0d[temp[0]] ^ Log_09[temp[1]];
*((unsigned char*)State+3) = Log_0e[temp[3]] ^ Log_0b[temp[0]] ^ Log_0d[temp[1]] ^ Log_09[temp[2]];
State --;
}
State -= 2;
}
Word -= Nb;
memcpy(State,State+Nb,12);
State += Nb+2;
for(r = Nb-1; r = 0; r--)
{
*(unsigned char*)State = iSbox[*(unsigned char*)State];
*((unsigned char*)State+1) = iSbox[*((unsigned char*)(State-1)+1)];
*((unsigned char*)State+2) = iSbox[*((unsigned char*)(State-2)+2)];
*((unsigned char*)State+3) = iSbox[*((unsigned char*)(State-3)+3)];
*State ^= Word[r];
State --;
}
}
/*
*--------------------------------------------
*|k0|k1|k2|k3|k4|k5|k6|k7|k8|k9|.......|Nk*4|
*--------------------------------------------
*Nr轮密钥库
*每个密钥列长度为Nb
*---------------------
*| k0 | k1 | k2 | k3 |
*---------------------
*| k4 | k5 | k6 | k7 |
*---------------------
*| k8 | k9 | ka | kb |
*---------------------
*| kc | kd | ke | kf |
*---------------------
*/
unsigned long* keyExpansion(byte* key, int Nb, int Nr, int Nk)
{
unsigned long *w =new unsigned long[Nb * (Nr+1)]; // 4 columns of bytes corresponds to a word
memcpy(w,key,Nk2);
unsigned long temp;
for (int c = Nk; c Nb * (Nr+1); ++c)
{
//把上一轮的最后一行放入temp
temp = w[c-1];
//判断是不是每一轮密钥的第一行
if (c % Nk == 0)
{
//左旋8位
temp = (temp8)|(temp24);
//查Sbox表
SubWord((byte*)temp);
temp ^= Rcon[c/Nk];
}
else if ( Nk 6 (c % Nk == 4) )
{
SubWord((byte*)temp);
}
//w[c-Nk] 为上一轮密钥的第一行
w[c] = w[c-Nk] ^ temp;
}
return w;
}
unsigned char* SubWord(unsigned char* word)
{
word[0] = Sbox[ word[0] ];
word[1] = Sbox[ word[1] ];
word[2] = Sbox[ word[2] ];
word[3] = Sbox[ word[3] ];
return word;
}
/*
释放AES结构和State和密钥库word
*/
void freeAES(AES *aes)
{
// for(int i=0;iNb;i++)
// {
// printf("%d\n",i);
// free(aes-State[i]);
// free(aes-Word[i]);
// }
// printf("sdffd");
}
算法破解就是找到加密算法的漏洞，进行技巧性的破解。
暴力破解是在知道加密算的情况下，用各种密码去测试。关于暴力破解也不是真正的暴力，有很多技术巧。如有效的密码字典就是一例。
AES目前没有算法浮出水面。
AES暴力破解与密码强度（如字串的MD5值就难，简单字串在密码字典排序告前，相对容易一些）和计算能力有关。但AES密钥长度太长，各种排列组合简直是天文数字，现有能力民间单机不可能破解。当然也可能一买彩票就中大奖，但似乎比那概率小得多。
我有现成AES的程序，是从OPENSSL的代码里面抽取出来的。你可以看看，算法什么都是有c语言源代码的。那个cbc的模式跟CFB/dd
dd class="sisifanyi46a2-4efd-59d8-4d7e dd attach f-light" data-dl='[{"fsid":"603436015015742","shareid":"951291258","uid":293978624,"qid":874625611,"rid":1996180055}]' data-url="zhidao.baidu/question/136221050968132365" data-si="1"a href="#" class="sisifanyi4efd-59d8-4d7e-013e dl-name"i class="sisifanyi59d8-4d7e-013e-5912 i-download"/a
